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How to use two different eth interfaces inside CT [message #37087]

Tue, 18 August 2009 10:27

Mistery
Messages: 8
Registered: August 2009

Junior Member

Hi, I have a OpenVZ node with the following network setup:

eth0 (public net) 212.40.207.7 / 255.255.255.0 vlan ID 2
eth1 (private net) 10.0.10.7 / 255.255.255.0 vlan ID 3

on this node, there is a CT configured with venet0 212.40.207.240 / 255.255.255.0

Public LAN access works fine inside CT, however now I need the CT to also access the private net.
I tried adding a private IP address (10.0.10.240) to the CT but it didn't solve my issue.
I also tried playing with vzctl --netif_add but wasn't able to access the private LAN.

Can you please explain what should I do to make the CT access both LANs ?

Thanks in advance for any help!

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Re: How to use two different eth interfaces inside CT [message #37116 is a reply to message #37087]

Wed, 19 August 2009 13:21

Mistery
Messages: 8
Registered: August 2009

Junior Member

Any tips on this matter ?

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Re: How to use two different eth interfaces inside CT [message #37119 is a reply to message #37087]

Wed, 19 August 2009 13:24

tomp
Messages: 64
Registered: August 2007

Member

If its a VLAN, I think you have to create a virtual bridge and then connect the VLAN interface on the hardware node to the virtual bridge.

Then create a veth device inside the container and attach that to the bridge on the hardware node.

There are some tutorials on bridging in the wiki. I don't think OpenVZ supports VLAN tagging yet, so this is your best way round it.

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Re: How to use two different eth interfaces inside CT [message #37120 is a reply to message #37119]

Wed, 19 August 2009 13:29

Mistery
Messages: 8
Registered: August 2009

Junior Member

Currently the VLAN is implemented on the switch itself, not on hardware nodes.
On OpenVZ hardware node I have two physical ethX interfaces connected to different switch's ports on different VLANs
Can you please explain step by step what exactly I need to do on hardware node / CT to try make it working ?
Thanks!

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